The lengths of pregnancies in a small rural village are normally distributed with a mean of 267 days and a standard deviation of 17 days. In what range would you expect to find the middle 50% of most pregnancies? Between and . If you were to draw samples of size 36 from this population, in what range would you expect to find the middle 50% of most averages for the lengths of pregnancies in the sample? Between and . Enter your answers as numbers. Your answers should be accurate to 1 decimal places.

Answer:Step-by-step explanation:Given that the lengths of pregnancies in a small rural village are normally distributed with a mean of 267 days and a standard deviation of 17 days.X is N(267,17) where x = length of pregnancies in daysFor middle 50% we must have on either side 25% areaHence z= ±0.675Corresponding x score would be[tex]267-0.675(17), 267+0.675(15)\\=(255.525,278.475)[/tex]---Sample size = n =36Std error of sample = [tex]\frac{17}{\sqrt{36} } =2.83[/tex]50% would be within[tex]267-0.675(2.83), 267+0.675(2.83)\\=(265.09,268.91)[/tex]=between 265.1 and 268.9